So here we are discussing solutions of the physics paper of this sem. Our aim is to help the students those are looking to join any of B.Tech tuition in Delhi for physics in coming semester, because following will give a knowledge of faculty member also, thus we can act as bridge between student and teacher.

Question:-1(a)  Two wavelengths of light (lambda)1 and and (lambda)2 are sent through a youngs double slit experimental set up simultaneously. What must be true concerning (lambda)1 and (lambda)2 if the third order bright fringe of (lambda)1 is to coincide with fourth order minima of (lambda)2

Answer:-
For solving this problem we have to use the formula of distance of nth bright band from center of screen to that band

x  =  n (lambda) (D) / [d]

And the formula of nth dark band from center of screen to that band

y  =  (2 m – 1) (lambda)D / [2d]

Where m and n both are integers. These are given to us. We have to put n = 3 and  m = 4 then we have to equate x and y then find the value of lambda.

Solution to this problem was being answered by Faculty member giving B.Tech tuition in Delhi, we tried to ask his name but he refused, you can set your class with the faculty member by contacting on this number:-9899927912

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